запроса синтаксическая ошибка в запросе MySQL

Question

Это мой запрос:

SELECT 
    `i`.`itemtype` AS `Item`, 
    `p`.`name` 
    (SELECT SUM(`i`.`count`) AS `Count` WHERE `itemtype` = 2148), 
    (SELECT SUM(`i`.`count`) * 100 AS `Count1` WHERE `itemtype` = 2152), 
    (SELECT SUM(`i`.`count`) * 10000 AS `Count2` WHERE `itemtype` = 2160) 
FROM `player_items` AS `i` 
LEFT JOIN `players` AS `p` ON (`p`.`id` = `i`.`player_id`) 
WHERE `i`.`itemtype` IN (2148, 2152, 2160) 
GROUP BY `i`.`itemtype` 
LIMIT 0, 30 

Когда я запускаю выше запрос в MySQL, я получаю сообщение об ошибке:

#1064 - You have an error in your SQL syntax; check the manual that corresponds 
to your MySQL server version for the right syntax to use near 
'SELECT SUM(`i`.`count`) AS `Count` WHERE `itemtype` = 2148) 
    , (SELECT SUM(`i`' at line 4 

Я совершенно не понимаю, что это означает, что я начинаю в MySQL.

Answer 1

Вы пропустили запятую после этой колонки:

`p`.`name` 

Рассмотрим этот запрос вместо:

SELECT i.itemtype AS Item 
    , p.name 
    , SUM(CASE 
      WHEN itemtype = 2148 THEN i.count 
      ELSE 0 
     END) AS Count 
    , SUM(CASE 
      WHEN itemtype = 2152 THEN i.count 
      ELSE 0 
     END) * 100 AS Count1 
    , SUM(CASE 
      WHEN itemtype = 2160 THEN i.count 
      ELSE 0 
     END) * 10000 AS Count2 
FROM player_items AS i 
LEFT JOIN players AS p ON i.player_id = p.id 
WHERE i.itemtype IN (2148, 2152, 2160) 
GROUP BY i.itemtype ASC 
LIMIT 0, 30 

просуммировать эти три колонки вместе, вы можете:

SELECT t.itemType AS Item, t.Count, t.Count1, t.Count2 
    , SUM(t.Count1, t.Count2, t.Count3) AS Total 
FROM 
(
    SELECT i.itemtype AS Item 
     , p.name 
     , SUM(CASE 
       WHEN itemtype = 2148 THEN i.count 
       ELSE 0 
      END) AS Count 
     , SUM(CASE 
       WHEN itemtype = 2152 THEN i.count 
       ELSE 0 
      END) * 100 AS Count1 
     , SUM(CASE 
       WHEN itemtype = 2160 THEN i.count 
       ELSE 0 
      END) * 10000 AS Count2 
    FROM player_items AS i 
    LEFT JOIN players AS p ON i.player_id = p.id 
    WHERE i.itemtype IN (2148, 2152, 2160) 
    GROUP BY i.itemtype ASC 
    LIMIT 0, 30 
) AS t 

Или вы могли бы добавить еще CASE

SELECT i.itemtype AS Item 
    , p.name 
    , SUM(CASE 
      WHEN itemtype = 2148 THEN i.count 
      ELSE 0 
     END) AS Count 
    , SUM(CASE 
      WHEN itemtype = 2152 THEN i.count 
      ELSE 0 
     END) * 100 AS Count1 
    , SUM(CASE 
      WHEN itemtype = 2160 THEN i.count 
      ELSE 0 
     END) * 10000 AS Count2 
    , SUM(CASE 
      WHEN itemtype = 2148 THEN i.count 
      WHEN itemtype = 2152 THEN (i.count * 100) 
      WHEN itemtype = 2160 THEN (i.count * 10000) 
      ELSE 0 
     END) AS Total 
FROM player_items AS i 
LEFT JOIN players AS p ON i.player_id = p.id 
WHERE i.itemtype IN (2148, 2152, 2160) 
GROUP BY i.itemtype ASC 
LIMIT 0, 30 

CASE statements делает ненужным для вам нужно запустить три дополнительных оператора SELECT, чтобы вернуть те же результаты.

Answer 2

во всех ваших SELECT SUM(...) вы не определите FROM player_items AS i

Answer 3

Неисправный: -

SELECT SUM(`i`.`count`) AS `Count` <-- missing FROM which table 

Правильно: -

SELECT SUM(`i`.`count`) AS `Count` FROM some_table ... 

Answer 4

Я полагаю, вы хотите что-то вроде этого:

SELECT p.name 
     ,i.itemtype 
     ,CASE itemtype 
     WHEN 2148 THEN count(*) 
     WHEN 2152 THEN count(*) * 100 
     WHEN 2160 THEN count(*) * 10000 
     END AS ct 
FROM players p 
LEFT JOIN player_items i ON p.id = i.player_id 
WHERE i.itemtype IN (2148, 2152, 2160) 
GROUP BY p.name, i.itemtype 
ORDER BY p.name, i.itemtype 
LIMIT 30; 

Или, может быть, это:

SELECT p.name 
     ,sum(CASE WHEN itemtype = 2148 THEN 1 ELSE 0 END) AS ct 
     ,sum(CASE WHEN itemtype = 2152 THEN 1 ELSE 0 END) * 100 AS ct1 
     ,sum(CASE WHEN itemtype = 2160 THEN 1 ELSE 0 END) * 10000 AS ct2 
FROM players p 
LEFT JOIN player_items i ON p.id = i.player_id 
WHERE i.itemtype IN (2148, 2152, 2160) 
GROUP BY p.name 
ORDER BY p.name 
LIMIT 30; 

working demo for this version См.

Answer 5

SELECT 
    `i`.`itemtype` AS `Item`, 
    `p`.`name *<{miss ','}>* 
    (SELECT SUM(`i`.`count`) AS `Count` *<miss from 'table'>* WHERE `itemtype` = 2148), 
    (SELECT SUM(`i`.`count`) * 100 AS `Count1` *<miss from 'table'>* WHERE `itemtype` = 2152), 
    (SELECT SUM(`i`.`count`) * 10000 AS `Count2` *<miss from 'table'>* WHERE `itemtype` = 2160)