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Несмотря на то, что я проверяю злонамеренный URL (http://fileserver03.com), пустой ответ возвращается с Google Safe Browsing API v4.API безопасного просмотра Google v4 - Пустой ответ
Вот код, я пробовал:
String postURL = https://safebrowsing.googleapis.com/v4/threatMatches:find?key=API_KEY
String requestBody = "{" +
" \"client\": {" +
" \"clientId\": \"twittersentidetector\"," +
" \"clientVersion\": \"1.0\"" +
" }," +
" \"threatInfo\": {" +
" \"threatTypes\": [\"MALWARE\", \"SOCIAL_ENGINEERING\"]," +
" \"platformTypes\": [\"ANY_PLATFORM\"]," +
" \"threatEntryTypes\": [\"URL\"]," +
" \"threatEntries\": [" +
" {\"url\": \"http://fileserver03.com\"}," +
" {\"url\": \"https://bing.com\"}," +
" {\"url\": \"https://yahoo.com\"}" +
" ]" +
" }" +
" }";
URL url = new URL(postURL);
HttpURLConnection con = (HttpURLConnection) url.openConnection();
con.setRequestMethod("POST");
con.setRequestProperty("User-Agent", USER_AGENT);
con.setRequestProperty("Accept-Language", "en-US,en;q=0.5");
con.setRequestProperty("Content-Type", "application/json");
con.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
wr.writeBytes(requestBody);
wr.flush();
wr.close();
int responseCode = con.getResponseCode();
System.out.println("Response Code: " + responseCode);
System.out.println("Response Message: " + con.getResponseMessage());
BufferedReader in = new BufferedReader(new InputStreamReader(con.getInputStream()));
String output;
StringBuffer response = new StringBuffer();
while ((output = in .readLine()) != null) {
response.append(output);
} in .close();
System.out.println("Response: " + response.toString());
Вот результат:
Response Code: 200
Response Message: OK
Response: {}