PHP массив Mysql Sub Menu

Question

Можете ли вы помочь в создании выпадающим меню (подменю) With The Mycode Cat.php ФАЙЛ Включить в заголовке меню

/////// (Home)////////// 
include_once("./includes/config.php") ; 

$mysqlQuery=new mysqlQueryClass(); 

$query="SELECT `catagory_id`, `name` FROM `catagories` WHERE `level` = 1"; 
$mysqlQuery->mysqlQueryWOF($query); 

while (list($catagory_id,$name) = mysql_fetch_array($mysqlQuery->result)) 
{     
    $cats .= "<b>::</b> <a href='cat-$catagory_id,start-0'>$name</a><br>"; 
} 



///(SubMenu level 2 About From Home)////// 
$mysqlQuery=new mysqlQueryClass(); 

$query="SELECT `catagory_id`, `name` FROM `catagories` WHERE `level` = 2"; 
$mysqlQuery->mysqlQueryWOF($query); 

while (list($catagory_id,$name) = mysql_fetch_array($mysqlQuery->result)) 
{ 
    $cats .= "<b>::</b> <a href='cat-$catagory_id,start-0'>$name</a><br>"; 
} 

Изображения: http://s12.postimg.org/v2yxhk8gt/2016_01_17_06_21_08.png Уровень 1 = Меню Level2 = SubMenu

Answer 1

$mysqlQuery=new mysqlQueryClass(); 

$query="SELECT a.`catagory_id` parent_cat_id, a.`name` parent_cat, b.category_id, b.name 
    FROM `catagories` a 
    LEFT JOIN `catagories` b on b.level = 2 and a.category_id = b.category 
    WHERE a.`level` = 1"; 

$mysqlQuery->mysqlQueryWOF($query); 
$id2name = array(); 
$cat_tree = array(); 

while (list($parent_id,$parent,$cat_id,$cat) = mysql_fetch_array($mysqlQuery->result)) { 
    $id2name[$parent_id] = $parent; 
    $id2name[$cat_id] = $cat; 
    $cat_tree[$parent_id][] = $cat_id; 
} 

foreach ($cat_tree as $parent_id => $child_ids) { 
    $name = $id2name[$parent_id]; 
    $cats .= "<b>::</b> <a href='cat-$parent_id,start-0'>$name</a><br>"; 

    foreach ($child_ids as $id) { 
    if (is_null($id)) continue; 
    $child = $id2name[$id]; 
    $cats .= "<b>::::</b> <a href='cat-$id,start-0'>$child</a><br>"; 
    } 
} 

Answer 2

Вы можете создавать меню и подменю, как как:

$mysqlQuery=new mysqlQueryClass(); 
$query="SELECT `catagory_id`, `name` FROM `catagories` WHERE `level` = 1"; 
$mysqlQuery->mysqlQueryWOF($query); 


while (list($catagory_id,$name) = mysql_fetch_array($mysqlQuery->result)) 
{     
     $cats .= "<b>::</b> <a href='cat-$catagory_id,start-0'>$name</a><br>"; 

    $query="SELECT `catagory_id`, `name` FROM `catagories` WHERE `level` = 2 AND main_category = ". $catagory_id ; 
    $mysqlQuery->mysqlQueryWOF($query); 
     while (list($scatagory_id,$sname) = mysql_fetch_array($mysqlQuery->result)) 
     {     
     $cats .= "<b>::</b> <a href='cat-$scatagory_id,start-0'>$sname</a><br>"; 

     } 
}