Я не могу получить mysqli_result

Question

$con = mysqli_connect('host', 'username', 'password'); 
// mysqli_select_db($con, 'mysql'); 
mysqli_select_db($con, 'db_name'); 
//set charset 
mysqli_set_charset($con, "utf8"); 
//query an sql 
//$res = mysqli_query($con, 'SELECT COUNT(`id`) AS `count` FROM `customer_wallet` WHERE `store` = 0'); 
$res = mysqli_query($con, 'SELECT * AS `count` FROM `customer_wallet`'); 
while ($row = mysqli_fetch_array($res)) { 
    echo $row['count']; 
} 
mysqli_free_result($res); 
mysqli_close($con); 

Этот код возвращает следующую ошибку, что я могу сделать?

Не удалось получить mysqli_result

Answer 1

$con = mysqli_connect('host', 'username', 'password','db_name') or die(mysqli_error()); 
// mysqli_select_db($con, 'mysql'); 
//set charset 
mysqli_set_charset($con, "utf8"); 
//query an sql 
//$res = mysqli_query($con, 'SELECT COUNT(`id`) AS `count` FROM `customer_wallet` WHERE `store` = 0'); 
$res = mysqli_query($con, "SELECT count(*) AS count FROM customer_wallet") or die(mysqli_error($con)); 
while ($row = mysqli_fetch_assoc($res)) { 
    echo $row['count']; 
} 
mysqli_free_result($res); 
mysqli_close($con);