Дата отображается снова и снова, как я могу сделать группу по

Question

Использование MS Access 2003

Мой запрос.

select a.personid, a.cardeventdate as newday, a.intime as intime, 
    max(b.cardeventdate) as prevday, b.outtime as outtime 
from (
    select personid, cardeventdate, min(cardeventtime) as Intime, 
     max(cardeventtime) as outtime 
    from (
     SELECT T_PERSON.cardno, T_PERSON.NAME, T_TITLE.TITLENAME, 
      T_CARDEVENT.personid, T_CARDEVENT.CARDEVENTDATE, 
      T_CARDEVENT.CARDEVENTTIME 
     FROM (
      T_TITLE INNER JOIN T_PERSON 
       ON T_TITLE.TITLECODE = T_PERSON.TITLECODE) 
      INNER JOIN T_CARDEVENT ON T_PERSON.PERSONID = T_CARDEVENT.PERSONID 
     ORDER BY T_PERSON.TITLECODE) 
    group by personid, cardeventdate 
    ) as a INNER JOIN (
    select personid, cardeventdate, min(cardeventtime) as Intime, 
     max(cardeventtime) as outtime 
    from (
     SELECT T_PERSON.cardno, T_PERSON.NAME, 
      T_TITLE.TITLENAME, T_CARDEVENT.personid, 
      T_CARDEVENT.CARDEVENTDATE, T_CARDEVENT.CARDEVENTTIME 
     FROM (T_TITLE INNER JOIN T_PERSON 
      ON T_TITLE.TITLECODE = T_PERSON.TITLECODE) INNER JOIN T_CARDEVENT ON 
      T_PERSON.PERSONID = T_CARDEVENT.PERSONID 
     ORDER BY T_PERSON.TITLECODE) 
    group by personid, cardeventdate) as b ON a.PERSONID = b.PERSONID 
AND a.CARDEVENTDATE > b.CARDEVENTDATE  
GROUP BY a.PERSONID, a.CARDEVENTDATE, a.intime, b.outtime 

Форма выше запрос, Выход

personid newday  intime prevday  outtime 

127   20081112 073540 20081111 073024 
127   20081113 073420 20081111 073024 
127   20081113 073420 20081112 122737 
127   20081117 073710 20081111 073024 
127   20081117 073710 20081113 073420 
127   20081117 073710 20081112 122737 
1496  20080819 081935 20080818 110555 
1496  20080903 064211 20080819 081935 
1496  20080903 064211 20080818 110555 
1496  20080904 124129 20080903 064254 
1496  20080904 124129 20080819 081935 
1496  20080904 124129 20080818 110555 
1496  20080908 134345 20080903 064254 
1496  20080908 134345 20080819 081935 
1496  20080908 134345 20080818 110555 
1496  20080908 134345 20080904 130936 
1606  20080831 132538 20080824 102744 
1696  20080825 143758 20080824 182058 
1696  20080831 121407 20080825 153204 
1696  20080831 121407 20080824 182058 
1696  20080901 110704 20080831 121407 
1696  20080901 110704 20080825 153204 
1696  20080901 110704 20080824 182058 
1696  20080902 103342 20080831 121407 

так далее ...

Дата снова и снова показывая, поэтому дата дисплей только один раз

Ожидаемый результат

personid newday intime prevday outtime 

127   20081112 073540 20081111 073024 
127   20081113 073420 20081112 122737 
127   20081117 073710 20081113 073024 

и так далее ...

Итак, из приведенного выше запроса, как я могу создать группу.

Запрос помощи?

Answer 1

Поместите DISTINCT в свой первый выбор

например.

select distinct a.personid, a.cardeventdate as newday,...