Оператор CASE с SUM SQL

Question

Может ли кто-нибудь помочь мне с правильным синтаксисом для приведенного ниже оператора CASE? Это часть представления, которое я создаю, когда цена возврата составляет половину стоимости расчетной стоимости в таблице рабочих мест, когда описание заряда имеет «Return» в нем. его высказывание неправильного синтаксиса ключевое слово ELSE. Заранее спасибо.

`

/****** Object: View [dbo].[MMXREPORT] Script Date: 11/08/2016 14:06:29 ******/ 
SET ANSI_NULLS ON 
GO 

SET QUOTED_IDENTIFIER ON 
GO 

Alter view [dbo].[MMXREPORT] AS 
DECLARE @output int 
SELECT isnull(Cus.CUSTOMERNUMBER,'') AS "ACCOUNT", 
     isnull(dbo.Jobs.DELDATEANDTIME,'') as "DELIVERY DATE" , 
     isnull(dbo.Jobs.JOBREFERENCE,'') AS "MMX REFERENCE", 
     isnull(dbo.Jobs.JOBNUMBER,'') AS "INDIGO REF", 
     isnull(dbo.Jobs.COLPOSTCODE,'') AS "COLLECTION POSTCODE", 
     isnull(dbo.Jobs.DELTOWN,'') AS "DELIVERY TOWN", 
     isnull(dbo.Jobs.DELLPOSTCODE,'') AS "DELIVERY POST CODE", 
       CASE when (select count (*) from jobcharge jobc inner join charge 
       on charge.chargeid = jobc.chargeid 
       where jobc.jobid = jobs.jobid and charge.description like '%return%') > 0 THEN 'YES' 
       ELSE 'NO' END as "RETURN AUTHORISED", 
     isnull(dbo.GetClarionTime (DELREADYAT),'') AS "PLANNED DELIVERY TIME", 
     '' AS "DRIVER ARRIVAL TIME", 
     '' AS "ENGINEER ARRIVAL TIME", 
     isnull(convert(char(5), dbo.Jobs.PODDATEANDTIME, 108),'') AS"POD TIME", 
     isnull(dbo.Jobs.PODNAME,'') AS"POD NAME", 
     isnull(dbo.Vehicle.VEHICLE,'') AS "VEHICLE SIZE", 
     isnull(dbo.Jobs.ACTUALMILEAGE,'0') AS "MILEAGE", 
     isnull(dbo.Jobs.CALCULATEDCOST,'') AS "MILEAGE PRICE", 

     SELECT @output = count (*) from jobcharge jobc inner join charge 
     ON charge.chargeid = jobc.chargeid 
     WHERE jobc.jobid = jobs.jobid AND charge.description LIKE '%return%' 
     CASE WHEN @output > 0 THEN SUM(JOBS.CALCULATEDCOST/2) 
     ELSE '0.00' END 
     AS "RETURN PRICE",   
     isnull((select sum (dbo.JobCharge.FLATRATE) from jobcharge inner join charge on charge.chargeid = jobcharge.chargeid 
     WHERE dbo.Charge.DESCRIPTION like '%congestion%' and jobcharge.jobid = jobs.jobid),0) AS "CONGESTION CHARGE", 

     '' AS "CONGESTION CHARGE COMMENTS", 

     isnull((select sum (dbo.JobCharge.FLATRATE) from jobcharge inner join charge on charge.chargeid = jobcharge.chargeid 
     WHERE dbo.Charge.DESCRIPTION like '%waiting time%' and jobcharge.jobid = jobs.jobid),0) AS "WAITING TIME CHARGE", 

     '' AS "WAITING TIME COMMENTS", 

     isnull((select sum (dbo.JobCharge.FLATRATE) from jobcharge inner join charge on charge.chargeid = jobcharge.chargeid 
     WHERE dbo.Charge.DESCRIPTION like '%hrs%' and jobcharge.jobid = jobs.jobid),0) AS "ANY OTHER CHARGES", 


     '' AS "ANY OTHER COMMENTS", 
     '' AS "TOTAL COST",JOBS.CUSTOMERID 

FROM   dbo.Jobs left outer JOIN 
       dbo.Vehicle ON dbo.Jobs.VEHICLEID = dbo.Vehicle.VEHICLEID left outer JOIN 
       -- dbo.JobCharge ON dbo.Jobs.JobID = dbo.JobCharge.JOBID left outer JOIN 
       dbo.Customer CUS ON dbo.Jobs.CUSTOMERID = CUS.CUSTOMERID 

` выше полный запрос.

Answer 1

Это должно работать:

DECLARE @output int 
select @output= count (*) from jobcharge jobc inner join charge 
     on charge.chargeid = jobc.chargeid 
     where jobc.jobid = jobs.jobid and charge.description like '%return%' 
CASE WHEN @output > 0 THEN SUM(JOBS.CALCULATEDCOST/2) 
     ELSE '0.00' END as "RETURN PRICE", 

Answer 2

кажется неполным запрос. Итак, я предположил, что должна быть таблица с именем «JOBS». Для этого pl попробуйте следовать.

SELECT 
    CASE WHEN (SELECT COUNT (*)FROM JOBCHARGE JOBC 
       INNER JOIN CHARGE ON CHARGE.CHARGEID = JOBC.CHARGEID 
       WHERE JOBC.JOBID = JOBS.JOBID 
       AND CHARGE.DESCRIPTION LIKE '%return%') > 0 
      THEN 
       SUM(JOBS.CALCULATEDCOST/2) 
      ELSE '0.00' 
    END as "RETURN PRICE" FROM JOBS 

Answer 3

Я думаю, что вам не нужна сумма нескольких строк, но только одно значение ...

CASE WHEN EXISTS(
    select 1 from jobcharge jobc inner join charge 
     ON charge.chargeid = jobc.chargeid 
    WHERE jobc.jobid = jobs.jobid AND charge.description LIKE '%return% 
) THEN jobs.CALCULATEDCOST/2 ELSE 0.00 END as "RETURN PRICE", 

Использование exists (select 1 ...) может быстрее, чем на select count() ...