Im пытается правой присоединиться к symfony. Я пробовал, как описано здесь Doctrine 2 - Outer join query и здесь Symfony - Using Outer Joins with Doctrine ORM.RIGHT JOIN doctrine
$query = $em->getRepository('AppBundle:raports')->createQueryBuilder('r')
->select('r')
->leftJoin('r.requestRaports rr WITH rr.formId = :formId', false)
->setParameter('formId', $requestId->getFormId())
->getQuery();
дает
SELECT
r0_.id AS id_0,
r0_.adminComment AS adminComment_1,
r0_.addDate AS addDate_2,
r0_.submitDate AS submitDate_3,
r0_.statusId AS statusId_4,
r0_.userId AS userId_5,
r0_.requestId AS requestId_6,
r0_.requestRaports AS requestRaports_7
FROM
raports r0_
LEFT JOIN request_raports r1_ ON r0_.requestRaports = r1_.id
AND (r1_.formId = ?)
Когда я пытаюсь
$query = $em->getRepository('AppBundle:raports')->createQueryBuilder('r')
->select('r')
->join('r.requestRaports rr WITH rr.formId = :formId', false)
->setParameter('formId', $requestId->getFormId())
->getQuery();
это выглядит, что
SELECT
r0_.id AS id_0,
r0_.adminComment AS adminComment_1,
r0_.addDate AS addDate_2,
r0_.submitDate AS submitDate_3,
r0_.statusId AS statusId_4,
r0_.userId AS userId_5,
r0_.requestId AS requestId_6,
r0_.requestRaports AS requestRaports_7
FROM
raports r0_
INNER JOIN request_raports r1_ ON r0_.requestRaports = r1_.id
AND (r1_.formId = ?)
Но я хочу запросить как
SELECT * FROM
raports
r ПРАВОЕ СОЕДИНЕНИЕ request_raports rr ON r.requestRaports
= rr.id
Как правильно заняться работой в doctrine2?