If/Else In Regular Expression Scripting

Question

Я пытаюсь что-то скриптовать для чтения частей отчета. Я думал, что знаю, как использовать if/else логику внутри этого, но я продолжаю получать ошибки.

Код:

printf "The report type is: " 
egrep -o 'METAR|SPECI' metar1.txt 

printf "Station: " 
egrep -o 'K[A-Z]{3}' metar1.txt 

printf "Day of the month: " 
date_time=$(egrep -o '[0-9]{6}Z' metar1.txt) 
echo "$date_time"|cut -c1-2 
printf "Time of day: " 
echo "$date_time"|cut -c3-6 

if [[ egrep 'AUTO' metar1.txt ]]; 
then 
    echo "This is a fully automated report." 
elif [[ egrep -o 'COR' metar1.txt ]]; 
then 
    echo "This is a corrected observation." 
else 
    echo "There is neither 'AUTO' or 'COR' in this report." 
fi 

wind_degree=$(egrep -o '\s[0-9]{5}G?[0-9]?[0-9]?KT\s' metar1.txt|cut -c2-4) 
wind_speed=$(egrep -o '\s[0-9]{5}G?[0-9]?[0-9]?KT\s' metar1.txt|cut -c5-6) 
printf "Winds are from $wind_degree degree at $wind_speed knots\n" 

Я получаю ошибки в строке 13:

line 13: conditional binary operator expected, 
line 13: syntax error near `'AUTO'', 
line 13: `if [[ egrep 'AUTO' metar1.txt ]];' 

Answer 1

Заменить if ... fi блок с:

if egrep 'AUTO' metar1.txt ; then 
    echo "This is a fully automated report." 
elif egrep -o 'COR' metar1.txt ; then 
    echo "This is a corrected observation." 
else 
    echo "There is neither 'AUTO' or 'COR' in this report." 
fi