У меня есть таблица с 60 столбцами и вы хотите вертикально разбить ее, больше или как разделение на другие маленькие таблицы, разделенные на столбцы. Как сделать вертикальное разбиение в базе данных с помощью postgres 9.2? сделал много из Google, но не смог найти ничего полезного.вертикальное разбиение базы данных в postgres 9.2
таблица, в которой я хочу вертикально раздел является:
CREATE TABLE insurance.vt_owner
(
regn_no character varying(10) NOT NULL,
regn_dt timestamp without time zone,
purchase_dt timestamp without time zone,
owner_sr numeric(5,0),
owner_name character varying(150),
pan_no character varying(10),
f_name character varying(150),
c_add1 character varying(50),
c_add2 character varying(50),
c_city character varying(50),
c_district character varying(30),
c_pincode character varying(6),
p_add1 character varying(50),
p_add2 character varying(50),
p_city character varying(50),
p_district character varying(30),
p_pincode character varying(6),
owner_cd numeric(5,0),
owner_cd_desc character varying(50),
regn_type character varying(1),
regn_type_desc character varying(50),
vh_class numeric(5,0),
vh_class_desc character varying(50),
chasi_no character varying(30),
eng_no character varying(30),
maker numeric(5,0),
maker_desc character varying(50),
maker_model character varying(50),
body_type character varying(3),
body_type_desc character varying(50),
no_cyl numeric(2,0),
hp character varying(10),
seat_cap numeric(3,0),
stand_cap numeric(3,0),
sleeper_cap numeric(2,0),
unld_wt numeric(9,0),
ld_wt numeric(9,0),
fuel numeric(3,0),
fuel_desc character varying(50),
color character varying(50),
manu_mon numeric(2,0),
manu_yr numeric(4,0),
fit_dt timestamp without time zone,
norms numeric(2,0),
norms_desc character varying(50),
wheelbase character varying(10),
cubic_cap character varying(10),
floor_area numeric(7,3),
ac_fiitted character(1),
audio_fiitted character(1),
video_fiitted character(1),
vch_purchase_as character(1),
vch_catg character(3),
dealer_cd numeric(5,0),
dealer_cd_desc character varying(50),
sale_amt numeric(9,0),
laser_code character varying(10),
garage_add character varying(50),
state_cd character varying(2) NOT NULL,
rto_cd character varying(3) NOT NULL,
CONSTRAINT vt_owner_pkey PRIMARY KEY (state_cd, rto_cd, regn_no)
)
WITH (
OIDS=FALSE
);
ALTER TABLE insurance.vt_owner
OWNER TO postgres;
-- Index: insurance."index_VT_OWNER"
-- DROP INDEX insurance."index_VT_OWNER";
CREATE INDEX "index_VT_OWNER"
ON insurance.vt_owner
USING btree
(regn_no COLLATE pg_catalog."default", chasi_no COLLATE pg_catalog."default", state_cd COLLATE pg_catalog."default", rto_cd COLLATE pg_catalog."default");
заранее спасибо
postgresql не поддерживает вертикальное разбиение. –