Как читать все атрибуты условно?

Question

Я хочу прочитать все атрибуты как IEnumerable, используя where where.

Так что я хочу, -

возвращение сотрудников в виде списка, где List = платежная ведомость

Ниже мой XML.

<Employees Table="ListColumns" StartAt="1" Output="Return"> 
    <Lists List="PayList"> 
    <Employee Start="51" Length="11" Name="Amount"/> 
    <Employee Start="62" Length="6" Name="Name"/> 
    <Employee Start="68" Length="50" Name="Reason"/> 
    <Employee Start="118" Length="7" Name="Action"/> 
    <Employee Start="125" Length="6" Name="First"/> 
    <Employee Start="131" Length="6" Name="Last"/> 
    <Employee Start="137" Length="40" Name="Payee"/> 
    <Employee Start="177" Length="6" Name="Banker"/> 
    <Employee Start="183" Length="19" Name="DateIssued"/> 
    <Employee Start="202" Length="19" Name="DateStopped"/> 
    </Lists> 
    <Lists List="ResponseList"> 
    <Employee Start="51" Length="11" Name="Amount"/> 
    <Employee Start="62" Length="6" Name="Name"/> 
    <Employee Start="68" Length="50" Name="Reason"/> 
    <Employee Start="118" Length="7" Name="Action"/> 
    <Employee Start="125" Length="6" Name="First"/> 
    <Employee Start="131" Length="6" Name="Last"/> 
    <Employee Start="137" Length="40" Name="Payee"/> 
    <Employee Start="177" Length="6" Name="Banker"/> 
    <Employee Start="183" Length="19" Name="DateIssued"/> 
    <Employee Start="202" Length="19" Name="DateStopped"/> 
    </Lists> 
</Employees> 

Answer 1

Вы System.Xml.Linq XElement класс

 XElement xml = XElement.Load("filePath"); 
     var payList = xml.Elements("Lists").Where(list => list.Attribute("List").Value == "PayList");