Как получить художник формы имя last.fm апи

Question

Я хочу, чтобы получить имя исполнителя из last.fm апи Вот код

$jsonData = file_get_contents('http://ws.audioscrobbler.com/2.0/?method=chart.gettoptracks&limit=56&api_key=MYAPIKEY&format=json'); 
      $jsonData = json_decode($jsonData, true); 
foreach ($jsonData['tracks']['track'] as $track) { 
       $title = $track['name']; 
       $image = $track['image'][3]['#text']; 
       echo '<div id="track_short"><div class="track_short"> 
       <a href="http://'.$SiteUrl.'/mp3-download-'.cano($title).'/" ><img src="'.$image.'" alt="'.$title.'"> 
       <div class="description"><p class="description_content">'.$title.'</p> 
       </div></a></div></div>'; 
} 

Пример данных API

{"tracks":{"track":[{"name":"Sorry","duration":"0","playcount":"1931615","listeners":"193074","mbid":"","url":"http://www.last.fm/music/Justin+Bieber/_/Sorry","streamable":{"#text":"0","fulltrack":"0"},"artist":{"name":"Justin Bieber","mbid":"e0140a67-e4d1-4f13-8a01-364355bee46e","url":"http://www.last.fm/music/Justin+Bieber"},"image":[{"#text":"http://img2-ak.lst.fm/i/u/34s/d5af34cbc048b190fc7369acdcf8655b.png","size":"small"},{"#text":"http://img2-ak.lst.fm/i/u/64s/d5af34cbc048b190fc7369acdcf8655b.png","size":"medium"},{"#text":"http://img2-ak.lst.fm/i/u/174s/d5af34cbc048b190fc7369acdcf8655b.png","size":"large"},{"#text":"http://img2-ak.lst.fm/i/u/300x300/d5af34cbc048b190fc7369acdcf8655b.png","size":"extralarge"}]}],"@attr":{"page":"1","perPage":"1","totalPages":"253572626","total":"253572626"}}} 

Answer 1

прохладные спасибо у меня есть правильный от: $phpArtist = $phpJson['tracks']['track'][0]['artist']; к: $Artist = $track['artist']['name']; и его работы, благодаря

Answer 2

Использование метода PHP json_decode():

$json = '{"tracks":{"track":[{"name":"Sorry","duration":"0","playcount":"1931615","listeners":"193074","mbid":"","url":"http://www.last.fm/music/Justin+Bieber/_/Sorry","streamable":{"#text":"0","fulltrack":"0"},"artist":{"name":"Justin Bieber","mbid":"e0140a67-e4d1-4f13-8a01-364355bee46e","url":"http://www.last.fm/music/Justin+Bieber"},"image":[{"#text":"http://img2-ak.lst.fm/i/u/34s/d5af34cbc048b190fc7369acdcf8655b.png","size":"small"},{"#text":"http://img2-ak.lst.fm/i/u/64s/d5af34cbc048b190fc7369acdcf8655b.png","size":"medium"},{"#text":"http://img2-ak.lst.fm/i/u/174s/d5af34cbc048b190fc7369acdcf8655b.png","size":"large"},{"#text":"http://img2-ak.lst.fm/i/u/300x300/d5af34cbc048b190fc7369acdcf8655b.png","size":"extralarge"}]}],"@attr":{"page":"1","perPage":"1","totalPages":"253572626","total":"253572626"}}}'; 
$phpJson = json_decode($json, true, 10); //4 is the depth of the JSON string, but you can make this a big number and it will still work 
$phpArtist = $phpJson['tracks']['track'][0]['artist']['name']; 

Сообщите мне, если это работает, или если php нуждается в настройке, у меня нет PHP-клиента прямо сейчас.