Выражение небулевого типа, указанное в контексте, где ожидается условие, рядом с 'и'. В SQL Server на CASE

Question

SELECT 
    d.district_id, d.district_name, d1.district_id, d1.district_name 
FROM 
    tbl_district d, tbl_district d1 
WHERE 
    CASE 
     WHEN (d.district_id % 2) != 0 
      THEN d.district_id 
    END 
    AND d1.district_id = d.district_id+1; 

Answer 1

Я предполагаю, что вы пытаетесь фильтровать нечетные числа

SELECT 
    d.district_id, d.district_name, d1.district_id, d1.district_name 
FROM 
    tbl_district d 
INNER JOIN tbl_district d1 
     ON d1.district_id = d.district_id+1 
WHERE (d.district_id % 2) != 0 

начать Кроме того, используя INNER JOIN вместо старого стиля запятую присоединиться

Если вы используете SQL SERVER 2012+, то вы можете использовать LEAD функция окна

SELECT * 
FROM (SELECT *, 
       Lead(district_id)OVER(ORDER BY district_id) AS next_dst, 
       Lead(district_name)OVER(ORDER BY district_id) AS next_name 
     FROM tbl_district) a 
WHERE a.district_id + 1 = a.next_dst 
     AND (district_id % 2) != 0 

Answer 2

«Случай, когда» - это значение, это не логическая операция.

Например:

SELECT 
d.district_id, d.district_name, d1.district_id, d1.district_name 
FROM 
tbl_district d, tbl_district d1 
WHERE 
CASE 
    WHEN (d.district_id % 2) != 0 
     THEN d.district_id 
END+1 = d1.district_id 

Answer 3

CREATE PROCEDURE [dbo].[EvenOdd_District] 
AS 
BEGIN 

     SELECT d.district_id ,d.district_name,d1.district_id ,d1.district_name 
     FROM tbl_district d,tbl_district d1 WHERE d.district_id= 
     CASE 
      when (d.district_id%2)!=0 then d.district_id 
     END 
     AND d1.district_id=d.district_id+1; 
END