PHP MSSQL DateDiff Между датой Завершено в следующем результате

Question

У меня есть таблица SQL, в которой есть строки заполненных данных из: перфорированные в разы, задачи, завершенные в течение дня, с последующим выбиванием времени. Мне нужно придумать запрос PHP MSSQL, чтобы получить прошедшее время между каждой строкой. Предпочтительно используют DATEDIFF(second, [Date Completed], [Date Completed])/3600.0 AS DiffDate.

Как его получить, чтобы сохранить Date Completed с первого результата, чтобы я мог использовать его в следующем результате, чтобы получить истекшее время между двумя датами?

Мой запрос выглядит следующим образом:

SELECT PDT_Mill_Capacity_Labor_Detail.[id], 
    users.alias, 
    PDT_Mill_Capacity_Labor_Detail.[Order Number], 
    PDT_Mill_Capacity_Labor_Detail.[Job Name], 
    PDT_Mill_Capacity_Labor_Detail.[Door Number], 
    PDT_Mill_Capacity_Labor_Detail.[Qty Display], 
    PDT_Mill_Capacity_Labor_Detail.[Door Counter], 
    PDT_Mill_Capacity_Labor_Detail.[Jamb Counter], 
    PDT_Mill_Capacity_Labor_Detail.[Work Center], 
    PDT_Mill_Capacity_Labor_Detail.[Completed By], 
    PDT_Mill_Capacity_Labor_Detail.[Date Completed], 
    PDT_Mill_Capacity_Labor_Detail.[Hours Earned], 
    PDT_Mill_Capacity_Labor_Detail.[Elapsed Time], 
    PDT_Mill_Capacity_Labor_Detail.[Applied Time], 
    PDT_Mill_Capacity_Labor_Detail.[ID] 

FROM users INNER JOIN PDT_Mill_Capacity_Labor_Detail 
    ON users.[Employee Number] = PDT_Mill_Capacity_Labor_Detail.[Completed By] 

WHERE [Completed By]='081' 
    AND ([Date Completed] >= '10/21/2015 00:00:00' 
    AND [Date Completed] <= '10/21/2015 23:59:59') 

GROUP BY 
    PDT_Mill_Capacity_Labor_Detail.[id], users.alias, 
    PDT_Mill_Capacity_Labor_Detail.[Order Number], 
    PDT_Mill_Capacity_Labor_Detail.[Job Name], 
    PDT_Mill_Capacity_Labor_Detail.[Door Number], 
    PDT_Mill_Capacity_Labor_Detail.[Qty Display], 
    PDT_Mill_Capacity_Labor_Detail.[Door Counter], 
    PDT_Mill_Capacity_Labor_Detail.[Jamb Counter], 
    PDT_Mill_Capacity_Labor_Detail.[Work Center], 
    PDT_Mill_Capacity_Labor_Detail.[Completed By], 
    PDT_Mill_Capacity_Labor_Detail.[Date Completed], 
    PDT_Mill_Capacity_Labor_Detail.[Hours Earned], 
    PDT_Mill_Capacity_Labor_Detail.[Elapsed Time], 
    PDT_Mill_Capacity_Labor_Detail.[Applied Time], 
    PDT_Mill_Capacity_Labor_Detail.[ID] 

ORDER BY [Completed By], [Date Completed] 

Результаты выглядит следующим образом ...

Work Station | Date Completed   | Elapsed Time | ID 
--------------------------------------------------------------- 
Punched In | 2015-10-21 05:58:00.000 |  0  | 6816 

Task1   | 2015-10-21 11:27:11.000 |  0  | 6212 

Task2   | 2015-10-21 11:27:33.000 |  0  | 6219 

Task3   | 2015-10-21 11:28:22.000 |  0  | 6651 

Punched Out | 2015-10-21 14:42:00.000 |  0  | 7318 

Answer 1

После приличные ночи сон я сумел переписать процесс вычисления истекшего времени между каждой задачей, используя следующий запрос, и удалось получить необходимые результаты ...

SELECT b.[id], a.[Completed By], 
a.[Date Completed] AS newDateCompleted, 
b.[Date Completed] AS oldDateCompleted, 
DATEDIFF(second, a.[Date Completed],b.[Date Completed])/3600.0 AS diff 
FROM(
    SELECT id, [Completed By], [Date Completed], 
     (
      SELECT count(*) 
      FROM PDT_Mill_Capacity_Labor_Detail 
      WHERE [Completed By]=T.[Completed By] AND [Date Completed]<T.[Date Completed] 
     )+1 
    AS rank1 
    FROM PDT_Mill_Capacity_Labor_Detail 
    AS T 
    ) 
AS a INNER JOIN 
    (
     SELECT id, [Completed By], [Date Completed], 
     (
      SELECT count(*) 
      FROM PDT_Mill_Capacity_Labor_Detail 
      WHERE [Completed By]=T1.[Completed By] AND [Date Completed]<T1.[Date Completed] 
     ) 
     AS rank2 
     FROM PDT_Mill_Capacity_Labor_Detail 
     AS T1 
    ) 
AS b ON (a.rank1=b.rank2) AND (a.[Completed By] = b.[Completed By]) 

WHERE a.[Completed By]='084' AND (a.[Date Completed] >='11/4/2015' AND a.[Date Completed] <='11/4/2015 23:59:59') 

ORDER BY a.[Completed By], a.[Date Completed] ASC