У вас очень хорошее начало, я сделал намного больше изменений, чем планировал ... получил немного в этом!
Сообщите мне, если у вас есть вопросы, я использовал один простой класс OOP, называемый ячейкой, который отслеживает значение и позицию ячейки, а также предоставляет функцию отображения, я преобразовал много ваших переменных и жестко закодированных чисел к константам (начинается с окончательного и имеет то же значение для всей программы)
вы заметите, что я оставил вам условия выигрыша!
Я надеюсь, что это полезно, я чувствую, что видение 2D-массивов, используемых в контексте, с которым вы знакомы, может помочь вам понять их!
Мой нормальный процесс с использованием 2D-массивов для обработки: использование Setup(), чтобы установить исходный массив значений использовать Draw() для вызова каждой функции дисплейной элемента использовать другие функции для изменения массива данных, которые функция отображения из клеток знает, как отобразить
главного файла
// Grid Size constants
final int GRID_COLUMNS = 10;
final int GRID_ROWS = 8;
// Display constants
final int CELL_SCALE = 80;
final int COIN_RADIUS = 75;
final int BOARD_PADDING = 100;
final color[] PLAYER_COLORS = new color[]{color(0), color(200, 10, 10), color(200, 200, 10)};
// cell values
final int EMPTY_CELL = 0;
final int PLAYER_1 = 1;
final int PLAYER_2 = 2;
// game data
Cell[][] grid = new Cell [GRID_COLUMNS][GRID_ROWS];
int currentPlayer;
void setup() {
size(1000, 800);
ellipseMode(CENTER); // only needs to be set once per sketch
setupBlankBoard();
}
// method to populate the array with blank cells, used to initiate and reset the game
void setupBlankBoard() {
currentPlayer = PLAYER_1; // reset game and start with first player
// populate array
for (int y=0; y < GRID_ROWS; y++) { // for every vertical row,
for (int x=0; x < GRID_COLUMNS; x++) { // for every horizontal cell in that row
// rather than translates I prefer to calculate the actual x,y position and just display it there,
// we add the padding offset to every cell, and then take the column/row times the width of the square cell
grid[x][y] = new Cell(BOARD_PADDING+x*CELL_SCALE, BOARD_PADDING+y*CELL_SCALE);
}
}
}
void changePlayers() {
if (currentPlayer == PLAYER_1) {
currentPlayer = PLAYER_2;
} else {
// already was player 2, so change to 1
currentPlayer = PLAYER_1;
}
}
boolean placeCoin(int column) {
boolean coinPlaced = false;
// now we know the column, we need to find the lowest cell in that column that is empty
for (int y = GRID_ROWS-1; y >= 0; y--) { // let's start at bottom and move up to reduce computations
// for every cell, test if it is empty
if (grid[column][y].isEmpty()) {
// if found a valid cell, place current players token and exit the loop (break)
grid[column][y].setValue(currentPlayer);
coinPlaced = true;
break;
}
}
return coinPlaced;
}
void checkCoins() {
// scan the array for 4 of the same value in a row
for (int y=0; y < GRID_ROWS; y++) { // for every vertical row,
for (int x=0; x < GRID_COLUMNS; x++) { // for every horizontal cell in that row
//grid[x][y]
// I will leave this to you ;)
// keep in mind to check neighbors all you need to do is add or subtract 1 from the x or y value
// however when you are at the edge of the board be careful not to try and look at a neighbor that is off the edge, you will get a null pointer or an array out of bounds exception
if (x+1<GRID_COLUMNS) {
Cell toTheRight = grid[x+1][y];
}
// for each cell you could look at the 3 above the current, 3 below the current, 3 to the right and 3 to the left, 3 diagnal in each direction and then manually try and find 4 adjacent same color cells
// or a bit more complicated is a recursive solution that checks its 8 immediate neighbor and for each that match the center cell run the same function to test its 8 neighbors keeping track of the current inARowCount and returning true when it is found.
// would be a bit hard because you would need to make sure the second cell doesn't follow back to the original cell, and start an endless loop
}
}
}
void draw() {
background(1, 1, 1);
noStroke();
// draw all cells
for (int y=0; y < GRID_ROWS; y++) { // for every vertical row,
for (int x=0; x < GRID_COLUMNS; x++) { // for every horizontal cell in that row
grid[x][y].display(); // draw this cell
}
}
// draw next coin floating above the board, contrain its positon to above the board
fill(PLAYER_COLORS[currentPlayer]);
int currentMouseX = constrain(mouseX, BOARD_PADDING+COIN_RADIUS/2, BOARD_PADDING+(GRID_COLUMNS*CELL_SCALE)-COIN_RADIUS/2);
//currentMouseX = 40*(ceil(abs(currentMouseX/40)));
ellipse(currentMouseX, BOARD_PADDING/2, COIN_RADIUS, COIN_RADIUS);
}
// press any key to rest the game, probably want to test for a certain key here!
void keyPressed() {
setupBlankBoard();
}
// on press attempt to place a coin
void mousePressed() {
int currentMouseX = constrain(mouseX, BOARD_PADDING+COIN_RADIUS/2, BOARD_PADDING+(GRID_COLUMNS*CELL_SCALE)-COIN_RADIUS/2);
// determine what column we are over
int column = (currentMouseX - BOARD_PADDING)/CELL_SCALE;
// if choice is a valid coin placement
if (placeCoin(column)) {
// toggle players if a coin was placed
changePlayers();
// after each placement check win conditions
checkCoins();
}
}
клеток Класс
class Cell {
int x, y;
int value; // 0 for empty, 1 for team 1, 2 for team 2 (constants defined at top of main file)
Cell(int x, int y) {
// default constructor to create empty cell
this(x, y, EMPTY_CELL);
}
// allows cell value to be set at creation
Cell(int x, int y, int value) {
this.x = x;
this.y = y;
this.value = value;
}
boolean setValue(int value){
value = constrain(value, EMPTY_CELL,PLAYER_2); // keeps it from setting a value outside of our range
if(this.value == EMPTY_CELL){
this.value = value;
return true; // placed
}
return false; // was not able to place it as there is already a value
}
boolean isEmpty(){
return this.value == EMPTY_CELL;
}
void display() {
fill(0, 0, 255);
rect(this.x, this.y, CELL_SCALE, CELL_SCALE);
// Draw Circle color based on current value, could simply just put fill(playerColors[this.value]); but this seems a bit more clear
if(this.value == EMPTY_CELL){
fill(PLAYER_COLORS[EMPTY_CELL]);
}else if(this.value == PLAYER_1){
fill(PLAYER_COLORS[PLAYER_1]); // red
}else if(this.value == PLAYER_2){
fill(PLAYER_COLORS[PLAYER_2]); // yellow
}
ellipse(this.x + CELL_SCALE/2, this.y + CELL_SCALE/2, COIN_RADIUS, COIN_RADIUS);
}
}