Я новичок в запросах Mdx, и у меня был вопрос о mdx, как можно извлечь первый член кортежей в наборе az новый набор в mdx? У меня есть запрос, как это:Извлечь первый член кортежей в наборе в MDX
WITH
SET [people in first date] AS
'Filter
(
{[VW Dim Customer Broker Branch].[Customer Title].[Customer Title]*[Vw Dim Date].[Shamsi Date].&[1388/06/01]:[Vw Dim Date].[Shamsi Date].&[1388/06/02]},
[Measures].[Trade Cnt]>3
) '
SET [people in second date] AS
'Filter
(
{[VW Dim Customer Broker Branch].[Customer Title].[Customer Title]*[Vw Dim Date].[Shamsi Date].&[1388/06/03]:[Vw Dim Date].[Shamsi Date].&[1388/06/04]},
[Measures].[Trade Cnt]>0
) '
/* SET [numberOfFirstItem] As
[people in first date].item(0)*/
member [measures].[numberOfPeopleInFirstDate] AS
DistinctCount([people in first date])
member [measures].[numberOfPeopleInFirstDate1] AS
Count([people in first date])
member [measures].[numberOfPeopleInSecondtDate] AS
DistinctCount([people in second date])
member [measures].[Ratio] AS
'(([measures].[numberOfPeopleInSecondtDate]-[measures].[numberOfPeopleInFirstDate])/IIF([measures].[numberOfPeopleInFirstDate]=0,1,[measures].[numberOfPeopleInFirstDate]))*100'
select
[Measures].[Trade Cnt] on 0,
[people in first date] on 1
--{[measures].[numberOfPeopleInFirstDate],[measures].[numberOfPeopleInSecondtDate],[measures].[Ratio]} on 0
/* {[Measures].[Trade Cnt]} on 0,
[people in first date] on 1*/
-- {[numberOfFirstItem]} on 0
from [DVPL]
Я хочу, чтобы извлечь первый член tuples
в первом сете - просто [VW Dim Customer Broker Branch].[Customer Title].[Customer Title]
, потому что я хочу отчетливый граф имя people
с упомянутым запросом T получил повторы имен.