1
Итак, я понимаю, что ВСЕ получат мне SELECTS, что я хотел бы отслеживать для своего приложения, однако демон POSTGRES запускает свой собственный вариант для базы данных и регистрирует его ...Logging = ALL issue on PostgresSQL 9.5 on Ubuntu 16.04
кто-нибудь знает, как избежать этого, как мой журнал будет заполняться довольно быстро
LOG: statement: SELECT
(SELECT sum(xact_commit) + sum(xact_rollback) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Transactions",
(SELECT sum(xact_commit) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Commits",
(SELECT sum(xact_rollback) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Rollbacks"
2017-01-09 23:53:36 UTC [14264-16] [email protected] LOG: statement: SELECT
(SELECT sum(xact_commit) + sum(xact_rollback) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Transactions",
(SELECT sum(xact_commit) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Commits",
(SELECT sum(xact_rollback) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Rollbacks"
2017-01-09 23:53:37 UTC [14264-17] [email protected] LOG: statement: SELECT
(SELECT sum(xact_commit) + sum(xact_rollback) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Transactions",
(SELECT sum(xact_commit) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Commits",
(SELECT sum(xact_rollback) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Rollbacks"
2017-01-09 23:53:38 UTC [14264-18] [email protected] LOG: statement: SELECT
(SELECT sum(xact_commit) + sum(xact_rollback) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Transactions",
(SELECT sum(xact_commit) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Commits",
(SELECT sum(xact_rollback) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Rollbacks"
2017-01-09 23:53:39 UTC [14264-19] [email protected] LOG: statement: SELECT
(SELECT sum(xact_commit) + sum(xact_rollback) FROM pg_stat_database WHERE datname = (SELECT datname FROM pg_database WHERE oid = 16384)) AS "Transactions", ....
...
...
Ну, что кажется почти слишком легко, поэтому, наверное, я не нашел ничего в межсети ... Большое спасибо – CBERBER
вы должны принять этот ответ, как правильно http://stackoverflow.com/помощь/кто-ответы – e4c5