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Мне нужно два случайных числа в каждом цикле, но они не могут использовать случайные числа предыдущего цикла. Я потерян, я искал и не знаю, что делать. Пожалуйста помоги! Я поставил свой код ниже. Итак, мне нужно, в частности, генерировать два случайных числа, хранящихся в n1 & n2. Затем, в следующем цикле, не используйте эти предыдущие числа. Тем не менее, их можно использовать после того, как они не использовались дважды подряд.loop rand(), на следующем rand() не использовать предыдущий?
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
int main()
{
//declare variables
int numAttempts = 3;
int response;
char playAgain;
int points;
bool previousAnswer;
srand(time(0));
//Welcome user to the program and explain the rules
cout << "\nWelcome! This is the Multiplication Practice Game!" << endl
<< "A multiplication problem will be presented which you must solve." << endl << endl
<< "THESE ARE THE RULES:" << endl
<< "*You start with 3 lives." << endl
<< "*Each correct answer earns you 5 points!" << endl
<< "*An incorrect answer results in 1 life lost." << endl
<< "*If you're incorrect but within 5 of the answer:" << endl
<< "\t-you are granted another attempt" << endl
<< "\t-you earn 3 points if correct" << endl
<< "\t-you lose a life if incorrect" << endl
<< "*Once you lose all of your lives, it's game over!" << endl << endl
<< "Good luck, let's begin..." << endl << endl;
//Do while numAttempts is not equal to 0
do{
//Random numbers for n1 and n2
int n1 = rand() % 13;
int n2 = rand() % 13;
//Present the problem and prompt for response
cout << "Answer the problem: ";
cout << n1 << "*"<< n2 << ": ";
cin >> response;
//If response is correct, congratulate
if(response == n1*n2)
{
cout << "CORRECT, great job. Keep going! \n\n";
points += 5;
previousAnswer = true;
}
//If response is not correct and lives are not equal to 0
if((response != (n1*n2)) && (numAttempts != 0))
{
//If response is not within 5 of the correct answer, no second chance and subtract 1 from numAttempts
if((response > (n1*n2)+5) || (response < (n1*n2)-5) || (previousAnswer != true))
{
cout << "That answer is incorrect." << endl;
numAttempts -= 1;
previousAnswer = false;
cout << "You have " << numAttempts << " lives remaining" << endl << endl;
}
//If response is within 5 of correct answer and previousAnswer is true, offer second attempt
if(response <= ((n1*n2)+5) && (response >= (n1*n2)-5) && (previousAnswer == true))
{
cout << "So close, try once more: ";
cin >> response;
if(response == n1 * n2)
{
cout << "CORRECT, great job. Keep going! \n\n";
points +=3;
previousAnswer = true;
}
//If answer is still incorrect, subtract 1 from numAttempts
else{
cout << "Sorry, that answer is still incorrect" << endl;
numAttempts -= 1;
previousAnswer = false;
cout << "You have " << numAttempts << " lives remaining" << endl << endl;
}
}
}
//If user runs out of lives, notify and ask if they would like to play again
if (0 == numAttempts)
{
cout << "You're all out of lives!" << endl
<< "Your total score is " << points << ", great job!" << endl
<< "Would you like to play again? Y/N: ";
cin >> playAgain;
if('y' == tolower(playAgain))
{
cout << "\nGreat! Let's try again! Good luck!" << endl;
numAttempts += 3;
cout << "Let's begin..." << endl << endl;
}else{
cout << "\nThanks for playing, see you next time!" << endl;
}
}
}while(numAttempts != 0); //ends loop if attempts are equal to 0
return 0;
}
Сохраните случайные значения предыдущей итерации в отдельных переменных (определенных вне цикла do) и сравните их с новыми. Если они используют то же самое, что и «продолжить», чтобы снова зациклиться и выбрать два новых. –
Спасибо! Я просто сделал заявление if в моем цикле, которое продолжится, если условия будут выполнены. Потрясающие. – Quadruckus
Чтобы указать, что ваша проблема решена, примите ответ. –