Excel Раундап против .NET Math.Round

Question

в Excel, =ROUNDUP(474.872126666666, 2) -> 474,88
в .NET,

Math.Round(474.87212666666666666666666666667, 2, MidpointRounding.ToEven) // 474.87 
Math.Round(474.87212666666666666666666666667, 2, MidpointRounding.AwayFromZero) // 474.87 

Мой клиент хотите Excel округление результата, есть ли способ я могу получить 474.88 в .NET?

спасибо

Answer 1

double ROUNDUP(double number, int digits) 
    { 
    return Math.Ceiling(number * Math.Pow(10, digits))/Math.Pow(10, digits); 
    } 

Answer 2

Math.Ceiling является то, что вы ищете.

Answer 3

Это моя попытка решения, которое ведет себя как функция Excel ROUNDUP. я попытался охватить такие случаи, как: отрицательные десятичные числа, отрицательные цифры (да Excel поддерживает это), больших десятичных значений

public static decimal RoundUp(decimal number, int digits) 
{ 
    if (digits > 0) 
    { 
     // numbers will have a format like +/-1.23, where the fractional part is optional if numbers are integral 
     // Excel RoundUp rounds negative numbers as if they were positive. 
     // To simulate this behavior we will use the absolute value of the number 
     // E.g. |1.23| = |-1.23| = 1.23 
     var absNumber = Math.Abs(number); 

     // Now take the integral part (E.g. for 1.23 is 1) 
     var absNumberIntegralPart = Decimal.Floor(absNumber); 

     // Now take the fractional part (E.g. for 1.23 is 0.23) 
     var fraction = (absNumber - absNumberIntegralPart); 

     // Multiply fractional part by the 10^number of digits we're rounding to 
     // E.g. For 1.23 with rounded to 1 digit it will be 0.23 * 10^1 = 2.3 
     // Then we round that value UP using Decimal.Ceiling and we transform it back to a fractional part by dividing it by 10^number of digits 
     // E.g. Decimal.Ceiling(0.23 * 10)/10 = Decimal.Ceiling(2.3)/10 = 3/10 = 0.3 
     var tenPower = (decimal)Math.Pow(10, digits); 
     var fractionRoundedUp = Decimal.Ceiling(fraction * tenPower)/tenPower; 

     // Now we add up the absolute part with the rounded up fractional part and we put back the negative sign if needed 
     // E.g. 1 + 0.3 = 1.3 
     return Math.Sign(number) * (absNumberIntegralPart + fractionRoundedUp); 
    } else if (digits == 0) 
    { 
     return Math.Sign(number) * Decimal.Ceiling(Math.Abs(number)); 
    } else if (digits < 0) 
    { 
     // negative digit rounding means that for RoundUp(149.12, -2) we will discard the fractional part, shift the decimal point on the left part 2 places before rounding up 
     // then replace all digits on the right of the decimal point with zeroes 
     // E.g. RoundUp(149.12, -2). Shift decimal point 2 places => 1.49. Now roundup(1.49) = 2 and we put 00 instead of 49 => 200 

     var absNumber = Math.Abs(number); 
     var absNumberIntegralPart = Decimal.Floor(absNumber); 
     var tenPower = (decimal)Math.Pow(10, -digits); 
     var absNumberIntegraPartRoundedUp = Decimal.Ceiling(absNumberIntegralPart/tenPower) * tenPower; 
     return Math.Sign(number)*absNumberIntegraPartRoundedUp; 
    } 

    return number; 
} 

     [TestMethod] 
     public void Can_RoundUp_Correctly() 
     { 
      Assert.AreEqual(1.466m, MathExtensions.RoundUp(1.4655m, 3)); 
      Assert.AreEqual(-1.466m, MathExtensions.RoundUp(-1.4655m, 3)); 
      Assert.AreEqual(150m, MathExtensions.RoundUp(149.001m, 0)); 
      Assert.AreEqual(-150m, MathExtensions.RoundUp(-149.001m, 0)); 
      Assert.AreEqual(149.2m, MathExtensions.RoundUp(149.12m, 1)); 
      Assert.AreEqual(149.12m, MathExtensions.RoundUp(149.12m, 2)); 
      Assert.AreEqual(1232m, MathExtensions.RoundUp(1232, 2)); 
      Assert.AreEqual(200m, MathExtensions.RoundUp(149.123m, -2)); 
      Assert.AreEqual(-200m, MathExtensions.RoundUp(-149.123m, -2)); 
      Assert.AreEqual(-20m, MathExtensions.RoundUp(-12.4655m, -1)); 
      Assert.AreEqual(1.67m, MathExtensions.RoundUp(1.666666666666666666666666666m, 2)); 
      Assert.AreEqual(1000000000000000000000000000m, MathExtensions.RoundUp(999999999999999999999999999m, -2)); 
      Assert.AreEqual(10000000000000m, MathExtensions.RoundUp(9999999999999.999m, 2)); 
     } 

Answer 4

Вот правильный расчет ROUNDUP и ROUNDDOWN:

private static object RoundDown(List<Expression> p) 
{ 
    var target = (decimal)p[0].Evaluate(); 
    var digits = (decimal)p[1].Evaluate(); 

    if (target < 0) return (Math.Ceiling((double)target * Math.Pow(10, (int)digits))/Math.Pow(10, (int)digits)); 

    return Math.Floor((double)target * Math.Pow(10, (int)digits))/Math.Pow(10, (int)digits); 
} 

private static object RoundUp(List<Expression> p) 
{ 
    var target = (decimal)p[0].Evaluate(); 
    var digits = (decimal)p[1].Evaluate(); 

    if (target < 0) return (Math.Floor((double)target * Math.Pow(10, (int)digits))/Math.Pow(10, (int)digits)); 
    return Math.Ceiling((double)target * Math.Pow(10, (int)digits))/Math.Pow(10, (int)digits); 
}