2012-05-10 2 views

ответ

1

Я понял.

class JoinedSubclassMapping : JoinedSubclassMapping<Subclass> 
{ 
    public JoinedSubclassMapping() 
    { 
     Key(key => 
     { 
      key.Columns(c => c.Name("keypart1"), c => c.Name("keypart2"), c => c.Name("keypart3")); 
     }); 
    } 
}