Соедините две таблицы и подсчитайте соответствующие столбцы из таблицы 2

Question

У меня есть две таблицы и вам нужна комбинированная таблица на основе обоих.

таблица, как это ....

Combine table last column 
show count 
from Table 2 columns (Subject1, Subject2, Subject3, Subject4, Subject5, Subject6) 
where table1.course = table2.course match 

На следующем рисунке показан результат:

Я использую MS SQL Server 2008. Я хочу, чтобы создать SQL-запрос и сохранить это как Views, так что я могу использовать его в приложении windows vb.net и показать его через отчет RDLC ......

Answer 1

Дайте этим запросом попробовать:

select t.Edate, 
t.Course, 
t.Subject, 
sum(case when t.Subject = t2.Subject1 or t.Subject = t2.Subject2 or t.Subject = t2.Subject3 or t.Subject = t2.Subject4 or t.Subject = t2.Subject5 or t.Subject = t2.Subject6 then 1 else 0 end) [Count] 
from Table1 t 
join Table2 t2 on t.Course = t2.Course 
group by t.Edate, t.Course, t.Subject 
order by t.Edate, t.Course 

SQLFiddle

Answer 2

Попробуйте этот пример ins TEAD:

SELECT  dbo.table1.Edate, dbo.table1.Course, dbo.table1.Subject AS SubjectTitle, COUNT(dbo.table2.Subject1) AS Subject1, COUNT(dbo.table2.Subject2) AS Subject2, COUNT(dbo.table2.Subject3) 
         AS Subject3, COUNT(dbo.table2.Subject4) AS Subject4, COUNT(dbo.table2.Subject5) AS Subject5, COUNT(dbo.table2.Subject6) AS Subject6 
FROM   dbo.table1 CROSS JOIN 
         dbo.table2 
GROUP BY dbo.table1.Edate, dbo.table1.Course, dbo.table1.Subject 

Answer 3

Вероятно, это

WITH subjectList AS 
(
    SELECT course, Subject1 as subject 
    FROM TABLE2 
    UNION ALL 
    SELECT course, Subject2 as subject 
    FROM TABLE2 
    UNION ALL 
    SELECT course, Subject3 as subject 
    FROM TABLE2 
    UNION ALL 
    SELECT course, Subject4 as subject 
    FROM TABLE2 
    UNION ALL 
    SELECT course, Subject5 as subject 
    FROM TABLE2 
    UNION ALL 
    SELECT course, Subject6 as subject 
    FROM TABLE2 
) 
SELECT T1.Edate, T1.course, sl.subject, count(*) as subject_count 
FROM TABLE1 T1 
JOIN subjectList sl on T1.Course = sl.course and T1.Subject = sl.subject 
GROUP BY T1.Edate, T1.course, sl.subject 

может быть это

WITH subjectList AS 
(
    SELECT course, Subject1 as subject 
    FROM TABLE2 
    UNION ALL 
    SELECT course, Subject2 as subject 
    FROM TABLE2 
    UNION ALL 
    SELECT course, Subject3 as subject 
    FROM TABLE2 
    UNION ALL 
    SELECT course, Subject4 as subject 
    FROM TABLE2 
    UNION ALL 
    SELECT course, Subject5 as subject 
    FROM TABLE2 
    UNION ALL 
    SELECT course, Subject6 as subject 
    FROM TABLE2 
) 
SELECT T1.Edate, T1.course, sl.subject, 
     count(*) OVER(PARTITION BY T1.course, sl.subject) as subject_by_course_count, 
     count(*) OVER(PARTITION BY sl.subject) as subject_count 
FROM TABLE1 T1 
JOIN subjectList sl on T1.Course = sl.course and T1.Subject = sl.subject 
GROUP BY T1.Edate, T1.course, sl.subject 

Answer 4

спасибо всем, я решил это с вашей помощью, если кто-то хочет, чтобы этот здесь:

select t.Edate,t.Etime, 
t.Course, 
t.Subject,t.Paper,t.Code, 
sum(case when t2.adcat = 'Regular' AND t.Subject = S.Subject then 1 else 0 end) [Reg], 
sum(case when t2.adcat = 'Private' AND t.Subject = S.Subject then 1 else 0 end) [Pri], 
sum(case when t2.adcat = 'Ex.' AND t.Subject = S.Subject then 1 else 0 end) [Ex], 
sum(case when t2.adcat = 'Back Paper' AND t.Subject = S.Subject then 1 else 0 end) [BP], 
sum(case when t2.adcat = 'Single Subject' AND t.Subject = S.Subject then 1 else 0 end) [SS], 
sum(case when t2.adcat = 'Improvement' AND t.Subject = S.Subject then 1 else 0 end) [Imp] 
from EXAMscheme t 
join tblstudetail t2 CROSS APPLY(VALUES (subjectI), (subjectII), (subjectIII), (subjectIV), (subjectV), (subjectVI)) AS S(subject) 
on t.Course = t2.Course and 
t.session = t.session and 
    t.session = '2015-16' and 
    t2.session = '2015-16' AND 
    t2.EXstatus = 'OK' 
group by t.Edate,t.Etime,t.Paper,t.Code, t.Course, t.Subject 
order by t.Edate, t.Course